BOND POLARITY, QUESTION, HAPE OF XENON TETRAFLOURIDE XeF4:

 



SHAPE OF XENON TETRAFLOURIDE XeF4:

             Ground state configuration of xenon is;

             56Xe = 2, 8, 18, 18, 8

             =152, 252, 2p6, 352, 306, 3d10, 452, 4p6, 4d10, 4f0, 552, 5p6.

             On orbital hybridization two electrons from  5 pare promoted to empty 4f orbital. Excited state configuration of Xenon is;

There are two lone pair and four bond pairs around the central xenon atom. The shape of XeF4 is square planer. Two lone pair occupy axial position and four bond pair angles are 900.

QUESTION:

             Antimony, Sb is in Group V of the periodic table atomic configuration of 5b is 51 with the electronic configuration of;

             515b = 2, 8, 18, 18, 5

            = 152, 252, 2p6, 352, 3p6, 3d10, 452, 4p6, 4d10, 4f0, 5s2, 5p3.          

             It former a series of salts which contains the 5bF5m- anion, the structure of which is a square base pyramidal. Deduce the total number of electrons around the antimony atom, the value of n and the oxidation number of 5b in this ion.

BONDPOLARITY:

 

                              Separation of +ve and –ve charge within a compound is called bond polarity and such compounds are called polar compounds. Due to this bond polarity some covalent compounds show ionic behavior e.g; hydrogen chloride gas readily dissolves in water to produce ionic solution. Similarly some ionic compounds due to extreme bond polarity shows typical covalent properties. e.g; Aluminum chloride is soluble in benzene (organic solvent) as well as it is subline solid i.e; having no crystal lattice.


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